QUESTION 1 The levelling data below relates to a flight of levels observed along the…

GEOM 2088 Introduction to Surveying

1

QUESTION 1

The levelling data below relates to a flight of levels observed along the centreline of a road. A sight has

also been taken to the underside of a footbridge over the road at chainage 2190. The chainage of each

point in the table below is its horizontal distance from a survey mark measured along the road centreline.

BS IS FS RL Chainage (m) Remarks

1.830 139.350 2050 Road Surface

1.732 2.730 2150 Road Surface

-1.098 2190 U/side of bridge

0.816 2.632 2250 Road Surface

1.207 1.726 2350 Road Surface

2.107 2450 Road Surface

a) Compute the reduced level of the points using the rise and fall method and apply all the

usual checks. [Do NOT apply any adjustment methods. Show your answers in meters

correct to 3 decimal places]

b) What is the average grade of the road centreline between chainages 2050 and 2450?

[Write your answer in percentage grade correct to 1 decimal place]

c) A short section of the road, between chainage 2160 and 2240, is missing as a result of the

washaway and is to be rebuilt. The tallest vehicle that will pass over the rebuilt section stands

4.10 m above the road surface. If the road is rebuilt in the same place from which it appears to

have been washed away, will the tallest vehicle pass safely under the bridge, or will it hit?

Explain your answer.

(2 + 1.5 + 1.5 = 5 marks)

GEOM 2088 Introduction to Surveying

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QUESTION 2

In the figures below (Figure 1 and Figure 2), calculate the bearings of all the sides in the

traverses, if the bearing of the line CB in Figure 1 is 305°40’02” and the bearing of the line FA

in Figure 2 is 331°20’40”. Provide your answers in sexagesimal system rounded to the nearest

1”. Note: figures are not to scale.

Figure 1 Figure 2

In Figure 1, calculate the bearings of: In Figure 2, calculate the bearings of:

AB = ? AB = ?

BC = ? BC = ?

CD = ? CD = ?

DA = ? DE = ?

EF = ?

(3 marks; 1/3 marks for each bearing)

A

B

C

D

85o

07’ 07’’

110o

30’ 45’’

72o

51’ 28’’

91o

30’ 40’’

A

B

C

D E

F

85o

15’ 10’’

103o

00’ 30’’

214o

31’ 27’’

248o

20’ 20’’

278o

13’ 43’’

167o

10’ 10’’

North

GEOM 2088 Introduction to Surveying

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QUESTION 3

Using the “Radiation” technique, the bearings and horizontal distances are measured between

the station pairs A-B, B-C, C-D, D-E and E-A. From these stations, bearings and horizontal

distances are also measured to six fence posts 1, 2, 3, 4, 5, 6. All these measurements are shown

in the figure below. The coordinates of A are Easting: 1000.000m, Northing: 5000.000m.

95 18’ 30”

321

57’ 41”

215 43’ 00”

163

27’ 40”

60

35’ 20”

357.36

215.68

582.63

666.389

382.87

A

B

C

D

E

1

2

3

4

5

6

271 54’

31.35

135

27’

29.84

58 31’

10.42

2

01 10’

3.55

135 26’

5.76

158

55’

2.88

a) Calculate the coordinates (Easting and Northing) of the fence posts 1, 2, 3, 4, 5, and 6.

Provide your answers in meters correct to 3 decimal places.

b) Calculate the bearings and horizontal distances between the fence post pairs 1-2, 2-3,

3-4, 4-5, and 5-6. Provide your answer for bearings in sexagesimal system rounded to

the nearest 1”, and for distances in meters rounded to the nearest 1mm.

(3 + 2 = 5 marks)

North

GEOM 2088 Introduction to Surveying

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QUESTION 4

A four-sided traverse is measured in the field, as illustrated below. Point A is a survey mark

with known coordinates of 1000.000E, 2500.000N.

From To Bearing Distance

A B 70º 30′ 00″ 78.934 m

B C ? 124.569 m

C D ? 298.012 m

D A ? 170.706 m

a) Determine the angular misclosure of the traverse ABCD. Provide your answer in

sexagesimal system rounded to the nearest 1”.

b) Determine the adjusted bearings of lines BC, CD, DA. Provide your answer in

sexagesimal system rounded to the nearest 1”.

c) Using the adjusted bearings and distances for the traverse ABCD, calculate the

following:

i. the linear misclosure (in meters correct to 3 decimal places)

ii. the precision in reciprocal form

d) remove the linear misclosure using Bowditch’s rule and calculate the adjusted

coordinates in meters correct to 3 decimal places.

(1 + 1.5 + (0.75 + 0.75) + 3 = 7 marks)

Internal Angle

A 83° 00′ 00?

B 228° 28′ 46?

C 13° 20′ 20?

D 35° 10′ 14?

Note: Not to scale

Attachments: Assignment-1-….pdfApr 28 2022 09:41 AM

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