In the fi gure, a converging lens (f1 = +20.0 cm) and a diverging lens (f2 = -15.0 cm) are separated

In the fi gure, a converging lens (f1 = +20.0 cm) and a diverging lens (f2 = -15.0 cm) are separated
In the fi gure, a converging lens (f1 = +20.0 cm) and a diverging lens (f2 = −15.0 cm) are separated by a distance of 10.0 cm. An object with a height of ho1 = 5.00 mm is placed at a distance of do1 = 45.0 cm to the left of the fi rst (converging) lens. Concepts: (i) Is the image produced by the fi rst (converging) lens real or virtual? (ii) As far as the second lens is concerned, what role does the image produced by the fi rst lens play? (iii) Note in the fi gure that the image produced by the fi rst lens is called the “fi rst image,” and it falls to the right of the second lens. This image acts as the object for the second lens. Normally, however, an object would lie to the left of the lens. How do we take into account that this object lies to the right of the diverging lens? (iv) How do we fi nd the location of the image produced by the second lens when its object is a virtual object? Calculation: What are (a) the image distance di1 and (b) the height hi1 of the image produced by the fi rst lens? (c) What is the object distance for the second (diverging) lens? Find (d) the image distance di2 and (e) the height hi2 of the image produced by the second lens. Apr 25 2022 08:12 PM