1. A paging system uses 16k pages. To answer this question, you will need to figure out the number..

1. A paging system uses 16k pages. To answer this question, you will need to figure out the number..
1. A paging system uses 16k pages. To answer this question, you will need to figure out the number of bits required to store 0..16k-1. This is how many bits are in the displacement (=N). Take the original logical address and find its last N bits. Enter this number for the displacement, in hexadecimal. Then take the remaining bits and this is the page number. Convert these bits, if necessary, from binary to hexadecimal to enter as the page number. a) The number of bits for the displacement (or offset) would be: _______________. For a logical address of 0xabcd, the displacement would be in hexadecimal: _______________ (Note, your answer should be in the form: 0x1234, where the answer starts with 0x, with no leading spaces or zeros). b) The page number would be: (Format this similarly: 0x_ with no leading zeroes.) _______________. You look up the page in the page table and the corresponding frame is frame 0x13. What is the complete physical address for the logical address 0xabcd? (Format your answer as specified above _______________   May 13 2022 07:27 PM

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